Base | Representation |
---|---|
bin | 11110000001011100111100… |
… | …110110100000110001011011 |
3 | 122022112000102021212120222202 |
4 | 132001130330312200301123 |
5 | 114301330334312111044 |
6 | 1144454520132440415 |
7 | 36545443016544641 |
oct | 3601347466406133 |
9 | 568460367776882 |
10 | 132041200503899 |
11 | 390883a4417435 |
12 | 12986576a7910b |
13 | 588a57c80b73b |
14 | 2486b8483b191 |
15 | 103ea64647c4e |
hex | 78173cda0c5b |
132041200503899 has 2 divisors, whose sum is σ = 132041200503900. Its totient is φ = 132041200503898.
The previous prime is 132041200503889. The next prime is 132041200503941. The reversal of 132041200503899 is 998305002140231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132041200503899 is a prime.
It is not a weakly prime, because it can be changed into another prime (132041200503889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66020600251949 + 66020600251950.
It is an arithmetic number, because the mean of its divisors is an integer number (66020600251950).
Almost surely, 2132041200503899 is an apocalyptic number.
132041200503899 is a deficient number, since it is larger than the sum of its proper divisors (1).
132041200503899 is an equidigital number, since it uses as much as digits as its factorization.
132041200503899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 47.
The spelling of 132041200503899 in words is "one hundred thirty-two trillion, forty-one billion, two hundred million, five hundred three thousand, eight hundred ninety-nine".
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