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132041404320034 = 21154710972362001
BaseRepresentation
bin11110000001011101001001…
…000000000000100100100010
3122022112000221111101112011111
4132001131021000000210202
5114301331244001220114
61144454552253133534
736545451043135036
oct3601351100004442
9568460844345144
10132041404320034
1139088499476520
121298661318a2aa
13588a5b2b009c1
142486ba39341c6
15103ea774a7bc4
hex781749000922

132041404320034 has 16 divisors (see below), whose sum is σ = 216462757575456. Its totient is φ = 59909096520000.

The previous prime is 132041404319999. The next prime is 132041404320041. The reversal of 132041404320034 is 430023404140231.

It is a super-2 number, since 2×1320414043200342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132041404319978 and 132041404320005.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5486168967 + ... + 5486193034.

It is an arithmetic number, because the mean of its divisors is an integer number (13528922348466).

Almost surely, 2132041404320034 is an apocalyptic number.

132041404320034 is a deficient number, since it is larger than the sum of its proper divisors (84421353255422).

132041404320034 is a wasteful number, since it uses less digits than its factorization.

132041404320034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10972362561.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 132041404320034 its reverse (430023404140231), we get a palindrome (562064808460265).

The spelling of 132041404320034 in words is "one hundred thirty-two trillion, forty-one billion, four hundred four million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 11 22 547 1094 6017 12034 10972362001 21944724002 120695982011 241391964022 6001882014547 12003764029094 66020702160017 132041404320034