Search a number
-
+
1320420421113 = 3440140140371
BaseRepresentation
bin10011001101101111001…
…100001010110111111001
311200020020100222022211020
4103031233030022313321
5133113210111433423
62450332012053053
7164253151251663
oct23155714126771
94606210868736
101320420421113
11469a949a4882
12193aa6164189
1397690913661
1447ca162d533
1524531a3a4e3
hex1336f30adf9

1320420421113 has 4 divisors (see below), whose sum is σ = 1760560561488. Its totient is φ = 880280280740.

The previous prime is 1320420421081. The next prime is 1320420421127. The reversal of 1320420421113 is 3111240240231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320420421113 - 25 = 1320420421081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1320420421163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220070070183 + ... + 220070070188.

It is an arithmetic number, because the mean of its divisors is an integer number (440140140372).

Almost surely, 21320420421113 is an apocalyptic number.

It is an amenable number.

1320420421113 is a deficient number, since it is larger than the sum of its proper divisors (440140140375).

1320420421113 is an equidigital number, since it uses as much as digits as its factorization.

1320420421113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440140140374.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1320420421113 its reverse (3111240240231), we get a palindrome (4431660661344).

The spelling of 1320420421113 in words is "one trillion, three hundred twenty billion, four hundred twenty million, four hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 440140140371 1320420421113