Base | Representation |
---|---|
bin | 1100000000100101100011… |
… | …1110000001110101000011 |
3 | 1201202022101221110022011002 |
4 | 3000021120332001311003 |
5 | 3212314221330421311 |
6 | 44025534053242215 |
7 | 2531654635121021 |
oct | 300113076016503 |
9 | 51668357408132 |
10 | 13204222123331 |
11 | 4230974178718 |
12 | 159309733336b |
13 | 74a1ca92b005 |
14 | 339132b5b711 |
15 | 17d71360a93b |
hex | c0258f81d43 |
13204222123331 has 2 divisors, whose sum is σ = 13204222123332. Its totient is φ = 13204222123330.
The previous prime is 13204222123319. The next prime is 13204222123349. The reversal of 13204222123331 is 13332122240231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13204222123331 is a prime.
It is a super-2 number, since 2×132042221233312 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13204222123294 and 13204222123303.
It is not a weakly prime, because it can be changed into another prime (13204222123931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602111061665 + 6602111061666.
It is an arithmetic number, because the mean of its divisors is an integer number (6602111061666).
Almost surely, 213204222123331 is an apocalyptic number.
13204222123331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204222123331 is an equidigital number, since it uses as much as digits as its factorization.
13204222123331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13204222123331 its reverse (13332122240231), we get a palindrome (26536344363562).
The spelling of 13204222123331 in words is "thirteen trillion, two hundred four billion, two hundred twenty-two million, one hundred twenty-three thousand, three hundred thirty-one".
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