132043323311241 has 4 divisors (see below), whose sum is σ = 176057764414992. Its totient is φ = 88028882207492.

The previous prime is 132043323311171. The next prime is 132043323311281. The reversal of 132043323311241 is 142113323340231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132043323311241 - 2¹⁹ = 132043322786953 is a prime.

It is not an unprimeable number, because it can be changed into a prime (132043323311281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22007220551871 + ... + 22007220551876.

It is an arithmetic number, because the mean of its divisors is an integer number (44014441103748).

Almost surely, 2^{132043323311241} is an apocalyptic number.

It is an amenable number.

132043323311241 is a deficient number, since it is larger than the sum of its proper divisors (44014441103751).

132043323311241 is an equidigital number, since it uses as much as digits as its factorization.

132043323311241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44014441103750.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 132043323311241 its reverse (142113323340231), we get a palindrome (274156646651472).

The spelling of 132043323311241 in words is "one hundred thirty-two trillion, forty-three billion, three hundred twenty-three million, three hundred eleven thousand, two hundred forty-one".