132043330209041 has 2 divisors, whose sum is σ = 132043330209042. Its totient is φ = 132043330209040.

The previous prime is 132043330209031. The next prime is 132043330209061. The reversal of 132043330209041 is 140902033340231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67660824384400 + 64382505824641 = 8225620^2 + 8023871^2 .

It is an emirp because it is prime and its reverse (140902033340231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132043330209041 - 2¹⁰ = 132043330208017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132043330208992 and 132043330209010.

It is not a weakly prime, because it can be changed into another prime (132043330209031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66021665104520 + 66021665104521.

It is an arithmetic number, because the mean of its divisors is an integer number (66021665104521).

Almost surely, 2^{132043330209041} is an apocalyptic number.

It is an amenable number.

132043330209041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132043330209041 is an equidigital number, since it uses as much as digits as its factorization.

132043330209041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 35.

Adding to 132043330209041 its reverse (140902033340231), we get a palindrome (272945363549272).

The spelling of 132043330209041 in words is "one hundred thirty-two trillion, forty-three billion, three hundred thirty million, two hundred nine thousand, forty-one".