Base | Representation |
---|---|
bin | 10011001101101111111… |
… | …101011000110101000011 |
3 | 11200020021021020211100011 |
4 | 103031233331120311003 |
5 | 133113221412321311 |
6 | 2450333152405351 |
7 | 164253366026533 |
oct | 23155775306503 |
9 | 4606237224304 |
10 | 1320433323331 |
11 | 469aa1207471 |
12 | 193aaa546857 |
13 | 976934b01c5 |
14 | 47ca322b4c3 |
15 | 24532c38321 |
hex | 1336ff58d43 |
1320433323331 has 2 divisors, whose sum is σ = 1320433323332. Its totient is φ = 1320433323330.
The previous prime is 1320433323233. The next prime is 1320433323359. The reversal of 1320433323331 is 1333233340231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320433323331 - 239 = 770677509443 is a prime.
It is a super-2 number, since 2×13204333233312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320433323293 and 1320433323302.
It is not a weakly prime, because it can be changed into another prime (1320433023331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660216661665 + 660216661666.
It is an arithmetic number, because the mean of its divisors is an integer number (660216661666).
Almost surely, 21320433323331 is an apocalyptic number.
1320433323331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320433323331 is an equidigital number, since it uses as much as digits as its factorization.
1320433323331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 31.
Adding to 1320433323331 its reverse (1333233340231), we get a palindrome (2653666663562).
The spelling of 1320433323331 in words is "one trillion, three hundred twenty billion, four hundred thirty-three million, three hundred twenty-three thousand, three hundred thirty-one".
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