Base | Representation |
---|---|
bin | 11110000001011111100101… |
… | …100001000000000100000011 |
3 | 122022112021201111110210001111 |
4 | 132001133211201000010003 |
5 | 114301402133213330103 |
6 | 1144500105015144151 |
7 | 36545603106644536 |
oct | 3601374541000403 |
9 | 568467644423044 |
10 | 132044030214403 |
11 | 3908961674785a |
12 | 12987026675057 |
13 | 588a910b3bc58 |
14 | 2486d72596a1d |
15 | 103eb7cca086d |
hex | 7817e5840103 |
132044030214403 has 8 divisors (see below), whose sum is σ = 134234313788880. Its totient is φ = 129854573328480.
The previous prime is 132044030214373. The next prime is 132044030214409. The reversal of 132044030214403 is 304412030440231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132044030214403 - 217 = 132044030083331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132044030214409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 206350033 + ... + 206988946.
It is an arithmetic number, because the mean of its divisors is an integer number (16779289223610).
Almost surely, 2132044030214403 is an apocalyptic number.
132044030214403 is a deficient number, since it is larger than the sum of its proper divisors (2190283574477).
132044030214403 is an equidigital number, since it uses as much as digits as its factorization.
132044030214403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 413344277.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 132044030214403 its reverse (304412030440231), we get a palindrome (436456060654634).
The spelling of 132044030214403 in words is "one hundred thirty-two trillion, forty-four billion, thirty million, two hundred fourteen thousand, four hundred three".
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