Base | Representation |
---|---|
bin | 11110000001011111110101… |
… | …110101110111100010100011 |
3 | 122022112022102120212121212011 |
4 | 132001133311311313202203 |
5 | 114301403213323314341 |
6 | 1144500152122013351 |
7 | 36545612644053205 |
oct | 3601376565674243 |
9 | 568468376777764 |
10 | 132044304119971 |
11 | 390897473190a1 |
12 | 129870a2347257 |
13 | 588a955801659 |
14 | 2486d9aad6775 |
15 | 103eb96d57b81 |
hex | 7817f5d778a3 |
132044304119971 has 2 divisors, whose sum is σ = 132044304119972. Its totient is φ = 132044304119970.
The previous prime is 132044304119939. The next prime is 132044304120007. The reversal of 132044304119971 is 179911403440231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132044304119971 - 25 = 132044304119939 is a prime.
It is a super-2 number, since 2×1320443041199712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132044304119071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022152059985 + 66022152059986.
It is an arithmetic number, because the mean of its divisors is an integer number (66022152059986).
Almost surely, 2132044304119971 is an apocalyptic number.
132044304119971 is a deficient number, since it is larger than the sum of its proper divisors (1).
132044304119971 is an equidigital number, since it uses as much as digits as its factorization.
132044304119971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 49.
The spelling of 132044304119971 in words is "one hundred thirty-two trillion, forty-four billion, three hundred four million, one hundred nineteen thousand, nine hundred seventy-one".
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