Base | Representation |
---|---|
bin | 111101011111001111… |
… | …1101100111101100011 |
3 | 110121211102222000222211 |
4 | 1322332133230331203 |
5 | 4130412010004142 |
6 | 140354410342551 |
7 | 12353124662035 |
oct | 1727637547543 |
9 | 417742860884 |
10 | 132045000547 |
11 | 50aaaa62329 |
12 | 2171172aa57 |
13 | c5b4776825 |
14 | 6568d19c55 |
15 | 367c664917 |
hex | 1ebe7ecf63 |
132045000547 has 2 divisors, whose sum is σ = 132045000548. Its totient is φ = 132045000546.
The previous prime is 132045000523. The next prime is 132045000553. The reversal of 132045000547 is 745000540231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132045000547 - 219 = 132044476259 is a prime.
It is not a weakly prime, because it can be changed into another prime (132045003547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022500273 + 66022500274.
It is an arithmetic number, because the mean of its divisors is an integer number (66022500274).
Almost surely, 2132045000547 is an apocalyptic number.
132045000547 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045000547 is an equidigital number, since it uses as much as digits as its factorization.
132045000547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 31.
Adding to 132045000547 its reverse (745000540231), we get a palindrome (877045540778).
The spelling of 132045000547 in words is "one hundred thirty-two billion, forty-five million, five hundred forty-seven", and thus it is an aban number.
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