132045377304457 has 2 divisors, whose sum is σ = 132045377304458. Its totient is φ = 132045377304456.

The previous prime is 132045377304419. The next prime is 132045377304461. The reversal of 132045377304457 is 754403773540231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100844897128336 + 31200480176121 = 10042156^2 + 5585739^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132045377304457 is a prime.

It is a super-3 number, since 3×132045377304457³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132045377304398 and 132045377304407.

It is not a weakly prime, because it can be changed into another prime (132045377314457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022688652228 + 66022688652229.

It is an arithmetic number, because the mean of its divisors is an integer number (66022688652229).

Almost surely, 2^{132045377304457} is an apocalyptic number.

It is an amenable number.

132045377304457 is a deficient number, since it is larger than the sum of its proper divisors (1).

132045377304457 is an equidigital number, since it uses as much as digits as its factorization.

132045377304457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29635200, while the sum is 55.

The spelling of 132045377304457 in words is "one hundred thirty-two trillion, forty-five billion, three hundred seventy-seven million, three hundred four thousand, four hundred fifty-seven".