Base | Representation |
---|---|
bin | 10011001101110010110… |
… | …100011111000011010011 |
3 | 11200020101121120100222221 |
4 | 103031302310133003103 |
5 | 133113321204234141 |
6 | 2450342025241511 |
7 | 164254521015115 |
oct | 23156264370323 |
9 | 4606347510887 |
10 | 1320481321171 |
11 | 46a01630aa01 |
12 | 193b02633297 |
13 | 976a04171ac |
14 | 47ca97633b5 |
15 | 24537069bd1 |
hex | 13372d1f0d3 |
1320481321171 has 4 divisors (see below), whose sum is σ = 1321628569344. Its totient is φ = 1319334073000.
The previous prime is 1320481321163. The next prime is 1320481321183. The reversal of 1320481321171 is 1711231840231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1320481321171 - 23 = 1320481321163 is a prime.
It is a super-2 number, since 2×13204813211712 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320481321141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 573622360 + ... + 573624661.
It is an arithmetic number, because the mean of its divisors is an integer number (330407142336).
Almost surely, 21320481321171 is an apocalyptic number.
1320481321171 is a deficient number, since it is larger than the sum of its proper divisors (1147248173).
1320481321171 is a wasteful number, since it uses less digits than its factorization.
1320481321171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1147248172.
The product of its (nonzero) digits is 8064, while the sum is 34.
The spelling of 1320481321171 in words is "one trillion, three hundred twenty billion, four hundred eighty-one million, three hundred twenty-one thousand, one hundred seventy-one".
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