Base | Representation |
---|---|
bin | 11110000001100101100011… |
… | …100101010010000000110011 |
3 | 122022112220021020001110112002 |
4 | 132001211203211102000303 |
5 | 114302003300144424021 |
6 | 1144503045040124215 |
7 | 36546221003132456 |
oct | 3601454345220063 |
9 | 568486236043462 |
10 | 132050440233011 |
11 | 39091305a666a3 |
12 | 1298831530666b |
13 | 588b3c2b46481 |
14 | 24873bda1749d |
15 | 103ee058ca50b |
hex | 781963952033 |
132050440233011 has 16 divisors (see below), whose sum is σ = 140609619649440. Its totient is φ = 123579308697600.
The previous prime is 132050440233007. The next prime is 132050440233013. The reversal of 132050440233011 is 110332044050231.
It is a cyclic number.
It is not a de Polignac number, because 132050440233011 - 22 = 132050440233007 is a prime.
It is a super-2 number, since 2×1320504402330112 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132050440233013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39716711 + ... + 42912911.
It is an arithmetic number, because the mean of its divisors is an integer number (8788101228090).
Almost surely, 2132050440233011 is an apocalyptic number.
132050440233011 is a deficient number, since it is larger than the sum of its proper divisors (8559179416429).
132050440233011 is a wasteful number, since it uses less digits than its factorization.
132050440233011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3209974.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 132050440233011 its reverse (110332044050231), we get a palindrome (242382484283242).
The spelling of 132050440233011 in words is "one hundred thirty-two trillion, fifty billion, four hundred forty million, two hundred thirty-three thousand, eleven".
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