Base | Representation |
---|---|
bin | 11110000001100110001011… |
… | …100001011001101010110001 |
3 | 122022112221222220220121201011 |
4 | 132001212023201121222301 |
5 | 114302011133214220213 |
6 | 1144503235334110521 |
7 | 36546243420503455 |
oct | 3601461341315261 |
9 | 568487886817634 |
10 | 132051110304433 |
11 | 3909161a224231 |
12 | 129884817ab441 |
13 | 588b49b907238 |
14 | 2487444a00665 |
15 | 103ee4463a03d |
hex | 78198b859ab1 |
132051110304433 has 16 divisors (see below), whose sum is σ = 143232145439040. Its totient is φ = 121249464793600.
The previous prime is 132051110304403. The next prime is 132051110304457. The reversal of 132051110304433 is 334403011150231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132051110304433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132051110304395 and 132051110304404.
It is not an unprimeable number, because it can be changed into a prime (132051110304403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30461478 + ... + 34525408.
It is an arithmetic number, because the mean of its divisors is an integer number (8952009089940).
Almost surely, 2132051110304433 is an apocalyptic number.
It is an amenable number.
132051110304433 is a deficient number, since it is larger than the sum of its proper divisors (11181035134607).
132051110304433 is a wasteful number, since it uses less digits than its factorization.
132051110304433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4110608.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132051110304433 its reverse (334403011150231), we get a palindrome (466454121454664).
The spelling of 132051110304433 in words is "one hundred thirty-two trillion, fifty-one billion, one hundred ten million, three hundred four thousand, four hundred thirty-three".
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