Base | Representation |
---|---|
bin | 11110000001100110100011… |
… | …011110001010110011010011 |
3 | 122022120000000220222110201121 |
4 | 132001212203132022303103 |
5 | 114302012444100012131 |
6 | 1144503343250143111 |
7 | 36546256400006224 |
oct | 3601464336126323 |
9 | 568500026873647 |
10 | 132051512110291 |
11 | 39091806012994 |
12 | 12988574281a97 |
13 | 588b533c2b797 |
14 | 248748211524b |
15 | 103ee69a58911 |
hex | 7819a378acd3 |
132051512110291 has 2 divisors, whose sum is σ = 132051512110292. Its totient is φ = 132051512110290.
The previous prime is 132051512110277. The next prime is 132051512110351. The reversal of 132051512110291 is 192011215150231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132051512110291 - 27 = 132051512110163 is a prime.
It is a super-2 number, since 2×1320515121102912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132051512116291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66025756055145 + 66025756055146.
It is an arithmetic number, because the mean of its divisors is an integer number (66025756055146).
Almost surely, 2132051512110291 is an apocalyptic number.
132051512110291 is a deficient number, since it is larger than the sum of its proper divisors (1).
132051512110291 is an equidigital number, since it uses as much as digits as its factorization.
132051512110291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 34.
The spelling of 132051512110291 in words is "one hundred thirty-two trillion, fifty-one billion, five hundred twelve million, one hundred ten thousand, two hundred ninety-one".
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