Base | Representation |
---|---|
bin | 11110000001100111000000… |
… | …100101001110111001010011 |
3 | 122022120001021221222022021122 |
4 | 132001213000211032321103 |
5 | 114302014444112020311 |
6 | 1144503503534112455 |
7 | 36546304450162631 |
oct | 3601470045167123 |
9 | 568501257868248 |
10 | 132052000501331 |
11 | 39091a36770349 |
12 | 1298868b94b72b |
13 | 588b5b117a871 |
14 | 24874cad28351 |
15 | 103ee9787c0db |
hex | 7819c094ee53 |
132052000501331 has 2 divisors, whose sum is σ = 132052000501332. Its totient is φ = 132052000501330.
The previous prime is 132052000501319. The next prime is 132052000501361. The reversal of 132052000501331 is 133105000250231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132052000501331 is a prime.
It is a super-2 number, since 2×1320520005013312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132052000501331.
It is not a weakly prime, because it can be changed into another prime (132052000501361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026000250665 + 66026000250666.
It is an arithmetic number, because the mean of its divisors is an integer number (66026000250666).
Almost surely, 2132052000501331 is an apocalyptic number.
132052000501331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132052000501331 is an equidigital number, since it uses as much as digits as its factorization.
132052000501331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 132052000501331 its reverse (133105000250231), we get a palindrome (265157000751562).
The spelling of 132052000501331 in words is "one hundred thirty-two trillion, fifty-two billion, five hundred one thousand, three hundred thirty-one".
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