Base | Representation |
---|---|
bin | 11110000001100111100001… |
… | …011110101001001010000001 |
3 | 122022120002201102111210010112 |
4 | 132001213201132221022001 |
5 | 114302022111410001032 |
6 | 1144504034411441105 |
7 | 36546324231344063 |
oct | 3601474136511201 |
9 | 568502642453115 |
10 | 132052552422017 |
11 | 3909219a26a547 |
12 | 12988804756195 |
13 | 588b66b611356 |
14 | 2487540357733 |
15 | 103eecb04e1b2 |
hex | 7819e17a9281 |
132052552422017 has 2 divisors, whose sum is σ = 132052552422018. Its totient is φ = 132052552422016.
The previous prime is 132052552421917. The next prime is 132052552422047. The reversal of 132052552422017 is 710224255250231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124862946775681 + 7189605646336 = 11174209^2 + 2681344^2 .
It is a cyclic number.
It is not a de Polignac number, because 132052552422017 - 28 = 132052552421761 is a prime.
It is not a weakly prime, because it can be changed into another prime (132052552422047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026276211008 + 66026276211009.
It is an arithmetic number, because the mean of its divisors is an integer number (66026276211009).
Almost surely, 2132052552422017 is an apocalyptic number.
It is an amenable number.
132052552422017 is a deficient number, since it is larger than the sum of its proper divisors (1).
132052552422017 is an equidigital number, since it uses as much as digits as its factorization.
132052552422017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336000, while the sum is 41.
The spelling of 132052552422017 in words is "one hundred thirty-two trillion, fifty-two billion, five hundred fifty-two million, four hundred twenty-two thousand, seventeen".
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