Base | Representation |
---|---|
bin | 10011001101110111110… |
… | …001110010100000000011 |
3 | 11200020121102002022120012 |
4 | 103031313301302200003 |
5 | 133114004003003413 |
6 | 2450354200135135 |
7 | 164256551022314 |
oct | 23156761624003 |
9 | 4606542068505 |
10 | 1320564500483 |
11 | 46a059262838 |
12 | 193b264674ab |
13 | 976b471b717 |
14 | 47cb681660b |
15 | 2453e4ea7a8 |
hex | 13377c72803 |
1320564500483 has 2 divisors, whose sum is σ = 1320564500484. Its totient is φ = 1320564500482.
The previous prime is 1320564500429. The next prime is 1320564500531. The reversal of 1320564500483 is 3840054650231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320564500483 - 236 = 1251845023747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1320564500483.
It is not a weakly prime, because it can be changed into another prime (1320564500413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660282250241 + 660282250242.
It is an arithmetic number, because the mean of its divisors is an integer number (660282250242).
Almost surely, 21320564500483 is an apocalyptic number.
1320564500483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320564500483 is an equidigital number, since it uses as much as digits as its factorization.
1320564500483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 1320564500483 in words is "one trillion, three hundred twenty billion, five hundred sixty-four million, five hundred thousand, four hundred eighty-three".
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