Base | Representation |
---|---|
bin | 10011001101111100100… |
… | …011001010001000100001 |
3 | 11200020210222201022111121 |
4 | 103031330203022020201 |
5 | 133114140001114301 |
6 | 2450410140012241 |
7 | 164261542316323 |
oct | 23157443121041 |
9 | 4606728638447 |
10 | 1320644551201 |
11 | 46a09a469058 |
12 | 193b49231081 |
13 | 976c8198c01 |
14 | 47cc32d3613 |
15 | 2454655e3a1 |
hex | 1337c8ca221 |
1320644551201 has 2 divisors, whose sum is σ = 1320644551202. Its totient is φ = 1320644551200.
The previous prime is 1320644551189. The next prime is 1320644551229. The reversal of 1320644551201 is 1021554460231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1152511749601 + 168132801600 = 1073551^2 + 410040^2 .
It is an emirp because it is prime and its reverse (1021554460231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1320644551201 - 231 = 1318497067553 is a prime.
It is not a weakly prime, because it can be changed into another prime (1320644551231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660322275600 + 660322275601.
It is an arithmetic number, because the mean of its divisors is an integer number (660322275601).
Almost surely, 21320644551201 is an apocalyptic number.
It is an amenable number.
1320644551201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320644551201 is an equidigital number, since it uses as much as digits as its factorization.
1320644551201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 1320644551201 in words is "one trillion, three hundred twenty billion, six hundred forty-four million, five hundred fifty-one thousand, two hundred one".
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