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13209595131401 is a prime number
BaseRepresentation
bin1100000000111001100100…
…1110011011011000001001
31201202211021101201101120222
43000032121032123120021
53212411222323201101
644032223151355425
72532235040000414
oct300163116333011
951684241641528
1013209595131401
114233181095159
121594136822b75
1374a875b3a426
143394c2598b7b
1517d92a19301b
hexc039939b609

13209595131401 has 2 divisors, whose sum is σ = 13209595131402. Its totient is φ = 13209595131400.

The previous prime is 13209595131353. The next prime is 13209595131407. The reversal of 13209595131401 is 10413159590231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9517990095376 + 3691605036025 = 3085124^2 + 1921355^2 .

It is a cyclic number.

It is not a de Polignac number, because 13209595131401 - 210 = 13209595130377 is a prime.

It is not a weakly prime, because it can be changed into another prime (13209595131407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604797565700 + 6604797565701.

It is an arithmetic number, because the mean of its divisors is an integer number (6604797565701).

Almost surely, 213209595131401 is an apocalyptic number.

It is an amenable number.

13209595131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13209595131401 is an equidigital number, since it uses as much as digits as its factorization.

13209595131401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145800, while the sum is 44.

The spelling of 13209595131401 in words is "thirteen trillion, two hundred nine billion, five hundred ninety-five million, one hundred thirty-one thousand, four hundred one".