Base | Representation |
---|---|
bin | 111101100000110011… |
… | …0010011010011110011 |
3 | 110121222001221001001122 |
4 | 1323001212103103303 |
5 | 4131013321442011 |
6 | 140403510252455 |
7 | 12354326334056 |
oct | 1730146232363 |
9 | 417861831048 |
10 | 132097062131 |
11 | 51027390a31 |
12 | 2172705712b |
13 | c5c24a43b8 |
14 | 6571bcca9d |
15 | 3681eea3db |
hex | 1ec19934f3 |
132097062131 has 4 divisors (see below), whose sum is σ = 132971877264. Its totient is φ = 131222247000.
The previous prime is 132097062073. The next prime is 132097062197. The reversal of 132097062131 is 131260790231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132097062131 - 226 = 132029953267 is a prime.
It is a super-2 number, since 2×1320970621312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132097062091 and 132097062100.
It is not an unprimeable number, because it can be changed into a prime (132097062931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437407340 + ... + 437407641.
It is an arithmetic number, because the mean of its divisors is an integer number (33242969316).
Almost surely, 2132097062131 is an apocalyptic number.
132097062131 is a deficient number, since it is larger than the sum of its proper divisors (874815133).
132097062131 is an equidigital number, since it uses as much as digits as its factorization.
132097062131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 874815132.
The product of its (nonzero) digits is 13608, while the sum is 35.
The spelling of 132097062131 in words is "one hundred thirty-two billion, ninety-seven million, sixty-two thousand, one hundred thirty-one".
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