Base | Representation |
---|---|
bin | 10011001110010000000… |
… | …100001000101010000011 |
3 | 11200021122210210120001221 |
4 | 103032100010020222003 |
5 | 133120322310304021 |
6 | 2450502433335511 |
7 | 164302626264601 |
oct | 23162004105203 |
9 | 4607583716057 |
10 | 1320971963011 |
11 | 46a248265428 |
12 | 19401aa07597 |
13 | 9774ac738cc |
14 | 47d149a0871 |
15 | 24565185241 |
hex | 13390108a83 |
1320971963011 has 2 divisors, whose sum is σ = 1320971963012. Its totient is φ = 1320971963010.
The previous prime is 1320971962957. The next prime is 1320971963093. The reversal of 1320971963011 is 1103691790231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1320971963011 - 229 = 1320435092099 is a prime.
It is a super-2 number, since 2×13209719630112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320971969011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660485981505 + 660485981506.
It is an arithmetic number, because the mean of its divisors is an integer number (660485981506).
Almost surely, 21320971963011 is an apocalyptic number.
1320971963011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320971963011 is an equidigital number, since it uses as much as digits as its factorization.
1320971963011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 1320971963011 in words is "one trillion, three hundred twenty billion, nine hundred seventy-one million, nine hundred sixty-three thousand, eleven".
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