Base | Representation |
---|---|
bin | 11110000010010011110011… |
… | …100010110000011001100011 |
3 | 122022201122110002220122002001 |
4 | 132002103303202300121203 |
5 | 114303312001113133103 |
6 | 1144541540452104431 |
7 | 36552626425242436 |
oct | 3602236342603143 |
9 | 568648402818061 |
10 | 132100100130403 |
11 | 39100379754609 |
12 | 12995a74305117 |
13 | 5892ca82b6c42 |
14 | 24899710d581d |
15 | 104136048e01d |
hex | 7824f38b0663 |
132100100130403 has 2 divisors, whose sum is σ = 132100100130404. Its totient is φ = 132100100130402.
The previous prime is 132100100130379. The next prime is 132100100130413. The reversal of 132100100130403 is 304031001001231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132100100130403 - 217 = 132100099999331 is a prime.
It is not a weakly prime, because it can be changed into another prime (132100100130413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050050065201 + 66050050065202.
It is an arithmetic number, because the mean of its divisors is an integer number (66050050065202).
Almost surely, 2132100100130403 is an apocalyptic number.
132100100130403 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100100130403 is an equidigital number, since it uses as much as digits as its factorization.
132100100130403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 132100100130403 its reverse (304031001001231), we get a palindrome (436131101131634).
The spelling of 132100100130403 in words is "one hundred thirty-two trillion, one hundred billion, one hundred million, one hundred thirty thousand, four hundred three".
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