Base | Representation |
---|---|
bin | 111101100000111011… |
… | …0001010011101100001 |
3 | 110121222100202021211221 |
4 | 1323001312022131201 |
5 | 4131020403021233 |
6 | 140404135335041 |
7 | 12354406562515 |
oct | 1730166123541 |
9 | 417870667757 |
10 | 132101220193 |
11 | 51029770a48 |
12 | 21728521481 |
13 | c5c32cbba7 |
14 | 6572592145 |
15 | 368256c42d |
hex | 1ec1d8a761 |
132101220193 has 2 divisors, whose sum is σ = 132101220194. Its totient is φ = 132101220192.
The previous prime is 132101220101. The next prime is 132101220241. The reversal of 132101220193 is 391022101231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131861218129 + 240002064 = 363127^2 + 15492^2 .
It is an emirp because it is prime and its reverse (391022101231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132101220193 is a prime.
It is not a weakly prime, because it can be changed into another prime (132101221193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050610096 + 66050610097.
It is an arithmetic number, because the mean of its divisors is an integer number (66050610097).
Almost surely, 2132101220193 is an apocalyptic number.
It is an amenable number.
132101220193 is a deficient number, since it is larger than the sum of its proper divisors (1).
132101220193 is an equidigital number, since it uses as much as digits as its factorization.
132101220193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 132101220193 in words is "one hundred thirty-two billion, one hundred one million, two hundred twenty thousand, one hundred ninety-three".
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