Base | Representation |
---|---|
bin | 10011001110010010111… |
… | …111010001100010100011 |
3 | 11200021210020002221001102 |
4 | 103032102333101202203 |
5 | 133120422340122243 |
6 | 2450511345025015 |
7 | 164304063255044 |
oct | 23162277214243 |
9 | 4607706087042 |
10 | 1321021020323 |
11 | 46a272a21964 |
12 | 19403332516b |
13 | 9775818bbc4 |
14 | 47d1b2d08cb |
15 | 245696259b8 |
hex | 13392fd18a3 |
1321021020323 has 2 divisors, whose sum is σ = 1321021020324. Its totient is φ = 1321021020322.
The previous prime is 1321021020313. The next prime is 1321021020383. The reversal of 1321021020323 is 3230201201231.
It is a weak prime.
It is an emirp because it is prime and its reverse (3230201201231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1321021020323 - 224 = 1321004243107 is a prime.
It is a super-2 number, since 2×13210210203232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1321021020295 and 1321021020304.
It is not a weakly prime, because it can be changed into another prime (1321021020313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660510510161 + 660510510162.
It is an arithmetic number, because the mean of its divisors is an integer number (660510510162).
Almost surely, 21321021020323 is an apocalyptic number.
1321021020323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321021020323 is an equidigital number, since it uses as much as digits as its factorization.
1321021020323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1321021020323 its reverse (3230201201231), we get a palindrome (4551222221554).
The spelling of 1321021020323 in words is "one trillion, three hundred twenty-one billion, twenty-one million, twenty thousand, three hundred twenty-three".
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