Base | Representation |
---|---|
bin | 11110000010010111100011… |
… | …001010001110100110000011 |
3 | 122022202000211021102222011202 |
4 | 132002113203022032212003 |
5 | 114303343214234413243 |
6 | 1144543443420531415 |
7 | 36553131151451261 |
oct | 3602274312164603 |
9 | 568660737388152 |
10 | 132104120232323 |
11 | 39102051a18698 |
12 | 129967b66b0b6b |
13 | 5893499126285 |
14 | 2489c32d9d431 |
15 | 10414e83854b8 |
hex | 7825e328e983 |
132104120232323 has 2 divisors, whose sum is σ = 132104120232324. Its totient is φ = 132104120232322.
The previous prime is 132104120232229. The next prime is 132104120232389. The reversal of 132104120232323 is 323232021401231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132104120232323 - 222 = 132104116038019 is a prime.
It is a super-3 number, since 3×1321041202323233 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (132104120232023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052060116161 + 66052060116162.
It is an arithmetic number, because the mean of its divisors is an integer number (66052060116162).
Almost surely, 2132104120232323 is an apocalyptic number.
132104120232323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132104120232323 is an equidigital number, since it uses as much as digits as its factorization.
132104120232323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 132104120232323 its reverse (323232021401231), we get a palindrome (455336141633554).
The spelling of 132104120232323 in words is "one hundred thirty-two trillion, one hundred four billion, one hundred twenty million, two hundred thirty-two thousand, three hundred twenty-three".
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