Base | Representation |
---|---|
bin | 111101100001000001… |
… | …0010101001101011011 |
3 | 110121222120202100100222 |
4 | 1323002002111031123 |
5 | 4131022212104242 |
6 | 140404331550255 |
7 | 12354445646216 |
oct | 1730202251533 |
9 | 417876670328 |
10 | 132104409947 |
11 | 5103054a504 |
12 | 217295bb38b |
13 | c5c3b77a13 |
14 | 6572b8277d |
15 | 368299c5d2 |
hex | 1ec209535b |
132104409947 has 2 divisors, whose sum is σ = 132104409948. Its totient is φ = 132104409946.
The previous prime is 132104409919. The next prime is 132104410001. The reversal of 132104409947 is 749904401231.
It is a weak prime.
It is an emirp because it is prime and its reverse (749904401231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132104409947 - 26 = 132104409883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132104409898 and 132104409907.
It is not a weakly prime, because it can be changed into another prime (132104409907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052204973 + 66052204974.
It is an arithmetic number, because the mean of its divisors is an integer number (66052204974).
Almost surely, 2132104409947 is an apocalyptic number.
132104409947 is a deficient number, since it is larger than the sum of its proper divisors (1).
132104409947 is an equidigital number, since it uses as much as digits as its factorization.
132104409947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 44.
The spelling of 132104409947 in words is "one hundred thirty-two billion, one hundred four million, four hundred nine thousand, nine hundred forty-seven".
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