Base | Representation |
---|---|
bin | 11110000010010111110101… |
… | …010001011110111100111011 |
3 | 122022202001121110021021111011 |
4 | 132002113311101132330323 |
5 | 114303344330033433334 |
6 | 1144543533514214351 |
7 | 36553141531500421 |
oct | 3602276521367473 |
9 | 568661543237434 |
10 | 132104424124219 |
11 | 39102198510118 |
12 | 129968804243b7 |
13 | 5893517087671 |
14 | 2489c614a7111 |
15 | 1041514db2564 |
hex | 7825f545ef3b |
132104424124219 has 2 divisors, whose sum is σ = 132104424124220. Its totient is φ = 132104424124218.
The previous prime is 132104424124199. The next prime is 132104424124307. The reversal of 132104424124219 is 912421424401231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132104424124219 is a prime.
It is a super-2 number, since 2×1321044241242192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132104424124019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052212062109 + 66052212062110.
It is an arithmetic number, because the mean of its divisors is an integer number (66052212062110).
Almost surely, 2132104424124219 is an apocalyptic number.
132104424124219 is a deficient number, since it is larger than the sum of its proper divisors (1).
132104424124219 is an equidigital number, since it uses as much as digits as its factorization.
132104424124219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 40.
The spelling of 132104424124219 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twenty-four million, one hundred twenty-four thousand, two hundred nineteen".
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