13211000042 has 4 divisors (see below), whose sum is σ = 19816500066. Its totient is φ = 6605500020.

The previous prime is 13210999987. The next prime is 13211000053. The reversal of 13211000042 is 24000011231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24000011231 = 7 ⋅3428573033.

It can be written as a sum of positive squares in only one way, i.e., 10724880721 + 2486119321 = 103561^2 + 49861^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13210999990 and 13211000026.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3302750009 + ... + 3302750012.

Almost surely, 2^13211000042 is an apocalyptic number.

13211000042 is a deficient number, since it is larger than the sum of its proper divisors (6605500024).

13211000042 is an equidigital number, since it uses as much as digits as its factorization.

13211000042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6605500023.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 13211000042 its reverse (24000011231), we get a palindrome (37211011273).

The spelling of 13211000042 in words is "thirteen billion, two hundred eleven million, forty-two", and thus it is an aban number.