132110331320137 has 2 divisors, whose sum is σ = 132110331320138. Its totient is φ = 132110331320136.

The previous prime is 132110331319987. The next prime is 132110331320173. The reversal of 132110331320137 is 731023133011231.

Together with next prime (132110331320173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105641477465616 + 26468853854521 = 10278204^2 + 5144789^2 .

It is a cyclic number.

It is not a de Polignac number, because 132110331320137 - 2²³ = 132110322931529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132110331320099 and 132110331320108.

It is not a weakly prime, because it can be changed into another prime (132110331330137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055165660068 + 66055165660069.

It is an arithmetic number, because the mean of its divisors is an integer number (66055165660069).

Almost surely, 2^{132110331320137} is an apocalyptic number.

It is an amenable number.

132110331320137 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110331320137 is an equidigital number, since it uses as much as digits as its factorization.

132110331320137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 31.

Adding to 132110331320137 its reverse (731023133011231), we get a palindrome (863133464331368).

The spelling of 132110331320137 in words is "one hundred thirty-two trillion, one hundred ten billion, three hundred thirty-one million, three hundred twenty thousand, one hundred thirty-seven".