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132110442433114 = 266055221216557
BaseRepresentation
bin11110000010011101011011…
…111111100000101001011010
3122022202122010212210001020121
4132002131123333200221122
5114303444141230324424
61144550411023343454
736553443630332455
oct3602353377405132
9568678125701217
10132110442433114
11391047a6706722
1212997a7ba51b8a
135893c65b93ba2
14248a2728c049c
151041768414ee4
hex78275bfe0a5a

132110442433114 has 4 divisors (see below), whose sum is σ = 198165663649674. Its totient is φ = 66055221216556.

The previous prime is 132110442433033. The next prime is 132110442433117. The reversal of 132110442433114 is 411334244011231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 116320905737089 + 15789536696025 = 10785217^2 + 3973605^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 132110442433114.

It is not an unprimeable number, because it can be changed into a prime (132110442433117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33027610608277 + ... + 33027610608280.

Almost surely, 2132110442433114 is an apocalyptic number.

132110442433114 is a deficient number, since it is larger than the sum of its proper divisors (66055221216560).

132110442433114 is an equidigital number, since it uses as much as digits as its factorization.

132110442433114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66055221216559.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 132110442433114 its reverse (411334244011231), we get a palindrome (543444686444345).

The spelling of 132110442433114 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred forty-two million, four hundred thirty-three thousand, one hundred fourteen".

Divisors: 1 2 66055221216557 132110442433114