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132112014051 = 344037338017
BaseRepresentation
bin111101100001001111…
…1010101101011100011
3110122000010001200020110
41323002133111223203
54131031133422201
6140405202542403
712354600406503
oct1730237255343
9418003050213
10132112014051
1151034873596
1221730067a03
13c5c560aba4
146573ba1a03
1536834a06d6
hex1ec27d5ae3

132112014051 has 4 divisors (see below), whose sum is σ = 176149352072. Its totient is φ = 88074676032.

The previous prime is 132112014037. The next prime is 132112014107. The reversal of 132112014051 is 150410211231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132112014051 - 25 = 132112014019 is a prime.

It is a super-2 number, since 2×1321120140512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132112013051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22018669006 + ... + 22018669011.

It is an arithmetic number, because the mean of its divisors is an integer number (44037338018).

Almost surely, 2132112014051 is an apocalyptic number.

132112014051 is a deficient number, since it is larger than the sum of its proper divisors (44037338021).

132112014051 is an equidigital number, since it uses as much as digits as its factorization.

132112014051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44037338020.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 132112014051 its reverse (150410211231), we get a palindrome (282522225282).

The spelling of 132112014051 in words is "one hundred thirty-two billion, one hundred twelve million, fourteen thousand, fifty-one".

Divisors: 1 3 44037338017 132112014051