Base | Representation |
---|---|
bin | 11110000010011111010011… |
… | …010011011011001101000001 |
3 | 122022202211022101100102011121 |
4 | 132002133103103123031001 |
5 | 114304012241200024101 |
6 | 1144551341411112241 |
7 | 36553544344513552 |
oct | 3602372323331501 |
9 | 568684271312147 |
10 | 132112444142401 |
11 | 39105633610518 |
12 | 1299833a2a2681 |
13 | 58941c47b9258 |
14 | 248a3c26a2329 |
15 | 10418340140a1 |
hex | 7827d34db341 |
132112444142401 has 2 divisors, whose sum is σ = 132112444142402. Its totient is φ = 132112444142400.
The previous prime is 132112444142387. The next prime is 132112444142429. The reversal of 132112444142401 is 104241444211231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118262145025600 + 13850299116801 = 10874840^2 + 3721599^2 .
It is a cyclic number.
It is not a de Polignac number, because 132112444142401 - 217 = 132112444011329 is a prime.
It is not a weakly prime, because it can be changed into another prime (132112444142501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056222071200 + 66056222071201.
It is an arithmetic number, because the mean of its divisors is an integer number (66056222071201).
Almost surely, 2132112444142401 is an apocalyptic number.
It is an amenable number.
132112444142401 is a deficient number, since it is larger than the sum of its proper divisors (1).
132112444142401 is an equidigital number, since it uses as much as digits as its factorization.
132112444142401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24576, while the sum is 34.
Adding to 132112444142401 its reverse (104241444211231), we get a palindrome (236353888353632).
The spelling of 132112444142401 in words is "one hundred thirty-two trillion, one hundred twelve billion, four hundred forty-four million, one hundred forty-two thousand, four hundred one".
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