Base | Representation |
---|---|
bin | 11110000010011111111010… |
… | …011101111001111010011011 |
3 | 122022202220000011201110012011 |
4 | 132002133322131321322123 |
5 | 114304020112401413201 |
6 | 1144551530522130351 |
7 | 36553566543436465 |
oct | 3602377235717233 |
9 | 568686004643164 |
10 | 132113101201051 |
11 | 391059404a03a3 |
12 | 129984a23509b7 |
13 | 589429a972059 |
14 | 248a445a5d135 |
15 | 1041871a53151 |
hex | 7827fa779e9b |
132113101201051 has 2 divisors, whose sum is σ = 132113101201052. Its totient is φ = 132113101201050.
The previous prime is 132113101200989. The next prime is 132113101201087. The reversal of 132113101201051 is 150102101311231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132113101201051 - 215 = 132113101168283 is a prime.
It is not a weakly prime, because it can be changed into another prime (132113101261051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056550600525 + 66056550600526.
It is an arithmetic number, because the mean of its divisors is an integer number (66056550600526).
Almost surely, 2132113101201051 is an apocalyptic number.
132113101201051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132113101201051 is an equidigital number, since it uses as much as digits as its factorization.
132113101201051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 132113101201051 its reverse (150102101311231), we get a palindrome (282215202512282).
The spelling of 132113101201051 in words is "one hundred thirty-two trillion, one hundred thirteen billion, one hundred one million, two hundred one thousand, fifty-one".
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