Base | Representation |
---|---|
bin | 10011001110011001100… |
… | …010110111010001010001 |
3 | 11200022001220002010220201 |
4 | 103032121202313101101 |
5 | 133121134014410301 |
6 | 2450530314335201 |
7 | 164306600220016 |
oct | 23163142672121 |
9 | 4608056063821 |
10 | 1321131013201 |
11 | 46a31a01916a |
12 | 19406412a501 |
13 | 97774bc0c4c |
14 | 47d2bb6370d |
15 | 24574101201 |
hex | 133998b7451 |
1321131013201 has 4 divisors (see below), whose sum is σ = 1321137121792. Its totient is φ = 1321124904612.
The previous prime is 1321131013133. The next prime is 1321131013207. The reversal of 1321131013201 is 1023101311231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1321131013201 - 211 = 1321131011153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1321131013207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2717505 + ... + 3166558.
It is an arithmetic number, because the mean of its divisors is an integer number (330284280448).
Almost surely, 21321131013201 is an apocalyptic number.
It is an amenable number.
1321131013201 is a deficient number, since it is larger than the sum of its proper divisors (6108591).
1321131013201 is an equidigital number, since it uses as much as digits as its factorization.
1321131013201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6108590.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1321131013201 its reverse (1023101311231), we get a palindrome (2344232324432).
The spelling of 1321131013201 in words is "one trillion, three hundred twenty-one billion, one hundred thirty-one million, thirteen thousand, two hundred one".
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