13211311011034 has 4 divisors (see below), whose sum is σ = 19816966516554. Its totient is φ = 6605655505516.

The previous prime is 13211311010951. The next prime is 13211311011103. The reversal of 13211311011034 is 43011011311231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12738581883225 + 472729127809 = 3569115^2 + 687553^2 .

It is a super-2 number, since 2×13211311011034² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13211311010996 and 13211311011014.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3302827752757 + ... + 3302827752760.

Almost surely, 2^{13211311011034} is an apocalyptic number.

13211311011034 is a deficient number, since it is larger than the sum of its proper divisors (6605655505520).

13211311011034 is an equidigital number, since it uses as much as digits as its factorization.

13211311011034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6605655505519.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13211311011034 its reverse (43011011311231), we get a palindrome (56222322322265).

The spelling of 13211311011034 in words is "thirteen trillion, two hundred eleven billion, three hundred eleven million, eleven thousand, thirty-four".