132113440310233 has 4 divisors (see below), whose sum is σ = 132165638432208. Its totient is φ = 132061242188260.

The previous prime is 132113440310161. The next prime is 132113440310251. The reversal of 132113440310233 is 332013044311231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132113440310233 is a prime.

It is a super-2 number, since 2×132113440310233² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132113440310195 and 132113440310204.

It is not an unprimeable number, because it can be changed into a prime (132113440311233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26099057191 + ... + 26099062252.

It is an arithmetic number, because the mean of its divisors is an integer number (33041409608052).

Almost surely, 2^{132113440310233} is an apocalyptic number.

It is an amenable number.

132113440310233 is a deficient number, since it is larger than the sum of its proper divisors (52198121975).

132113440310233 is an equidigital number, since it uses as much as digits as its factorization.

132113440310233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52198121974.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 132113440310233 its reverse (332013044311231), we get a palindrome (464126484621464).

The spelling of 132113440310233 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four hundred forty million, three hundred ten thousand, two hundred thirty-three".