Base | Representation |
---|---|
bin | 1100000001000000000101… |
… | …1111000001001111011011 |
3 | 1201202222210022002221021011 |
4 | 3000100001133001033123 |
5 | 3212423313120430014 |
6 | 44033112514354351 |
7 | 2532326266533223 |
oct | 300200137011733 |
9 | 51688708087234 |
10 | 13211344311259 |
11 | 4233999498946 |
12 | 159454458b9b7 |
13 | 74aa943459b3 |
14 | 33960aa03083 |
15 | 17d9cda0d7c4 |
hex | c04017c13db |
13211344311259 has 2 divisors, whose sum is σ = 13211344311260. Its totient is φ = 13211344311258.
The previous prime is 13211344311199. The next prime is 13211344311311. The reversal of 13211344311259 is 95211344311231.
It is a strong prime.
It is an emirp because it is prime and its reverse (95211344311231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13211344311259 - 211 = 13211344309211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13211344311059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605672155629 + 6605672155630.
It is an arithmetic number, because the mean of its divisors is an integer number (6605672155630).
Almost surely, 213211344311259 is an apocalyptic number.
13211344311259 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211344311259 is an equidigital number, since it uses as much as digits as its factorization.
13211344311259 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 40.
The spelling of 13211344311259 in words is "thirteen trillion, two hundred eleven billion, three hundred forty-four million, three hundred eleven thousand, two hundred fifty-nine".
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