1321140132001 has 2 divisors, whose sum is σ = 1321140132002. Its totient is φ = 1321140132000.

The previous prime is 1321140131951. The next prime is 1321140132023. The reversal of 1321140132001 is 1002310411231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 843548565601 + 477591566400 = 918449^2 + 691080^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321140132001 - 2⁷ = 1321140131873 is a prime.

It is a super-2 number, since 2×1321140132001² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1321140132001.

It is not a weakly prime, because it can be changed into another prime (1321140132071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660570066000 + 660570066001.

It is an arithmetic number, because the mean of its divisors is an integer number (660570066001).

Almost surely, 2^{1321140132001} is an apocalyptic number.

It is an amenable number.

1321140132001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321140132001 is an equidigital number, since it uses as much as digits as its factorization.

1321140132001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1321140132001 its reverse (1002310411231), we get a palindrome (2323450543232).

The spelling of 1321140132001 in words is "one trillion, three hundred twenty-one billion, one hundred forty million, one hundred thirty-two thousand, one".