132114212223041 has 4 divisors (see below), whose sum is σ = 133154481610752. Its totient is φ = 131073942835332.

The previous prime is 132114212223031. The next prime is 132114212223047. The reversal of 132114212223041 is 140322212411231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132114212223041 - 2¹⁰ = 132114212222017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132114212222995 and 132114212223013.

It is not an unprimeable number, because it can be changed into a prime (132114212223047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520134693665 + ... + 520134693918.

It is an arithmetic number, because the mean of its divisors is an integer number (33288620402688).

Almost surely, 2^{132114212223041} is an apocalyptic number.

It is an amenable number.

132114212223041 is a deficient number, since it is larger than the sum of its proper divisors (1040269387711).

132114212223041 is a wasteful number, since it uses less digits than its factorization.

132114212223041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1040269387710.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 132114212223041 its reverse (140322212411231), we get a palindrome (272436424634272).

The spelling of 132114212223041 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred twelve million, two hundred twenty-three thousand, forty-one".