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132114223131113 is a prime number
BaseRepresentation
bin11110000010100000111101…
…010101101110100111101001
3122022202222220100211101220102
4132002200331111232213221
5114304024412110143423
61144552234121035145
736553636415620556
oct3602407525564751
9568688810741812
10132114223131113
1139106366824023
1212998756025ab5
1358944192307b2
14248a510a69a2d
1510418da2bbc28
hex78283d56e9e9

132114223131113 has 2 divisors, whose sum is σ = 132114223131114. Its totient is φ = 132114223131112.

The previous prime is 132114223131019. The next prime is 132114223131119. The reversal of 132114223131113 is 311131322411231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117814352309824 + 14299870821289 = 10854232^2 + 3781517^2 .

It is a cyclic number.

It is not a de Polignac number, because 132114223131113 - 232 = 132109928163817 is a prime.

It is not a weakly prime, because it can be changed into another prime (132114223131119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057111565556 + 66057111565557.

It is an arithmetic number, because the mean of its divisors is an integer number (66057111565557).

Almost surely, 2132114223131113 is an apocalyptic number.

It is an amenable number.

132114223131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114223131113 is an equidigital number, since it uses as much as digits as its factorization.

132114223131113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 29.

Adding to 132114223131113 its reverse (311131322411231), we get a palindrome (443245545542344).

The spelling of 132114223131113 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred twenty-three million, one hundred thirty-one thousand, one hundred thirteen".