Base | Representation |
---|---|
bin | 11110000010100000111101… |
… | …010101101110100111101001 |
3 | 122022202222220100211101220102 |
4 | 132002200331111232213221 |
5 | 114304024412110143423 |
6 | 1144552234121035145 |
7 | 36553636415620556 |
oct | 3602407525564751 |
9 | 568688810741812 |
10 | 132114223131113 |
11 | 39106366824023 |
12 | 12998756025ab5 |
13 | 58944192307b2 |
14 | 248a510a69a2d |
15 | 10418da2bbc28 |
hex | 78283d56e9e9 |
132114223131113 has 2 divisors, whose sum is σ = 132114223131114. Its totient is φ = 132114223131112.
The previous prime is 132114223131019. The next prime is 132114223131119. The reversal of 132114223131113 is 311131322411231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117814352309824 + 14299870821289 = 10854232^2 + 3781517^2 .
It is a cyclic number.
It is not a de Polignac number, because 132114223131113 - 232 = 132109928163817 is a prime.
It is not a weakly prime, because it can be changed into another prime (132114223131119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057111565556 + 66057111565557.
It is an arithmetic number, because the mean of its divisors is an integer number (66057111565557).
Almost surely, 2132114223131113 is an apocalyptic number.
It is an amenable number.
132114223131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114223131113 is an equidigital number, since it uses as much as digits as its factorization.
132114223131113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 29.
Adding to 132114223131113 its reverse (311131322411231), we get a palindrome (443245545542344).
The spelling of 132114223131113 in words is "one hundred thirty-two trillion, one hundred fourteen billion, two hundred twenty-three million, one hundred thirty-one thousand, one hundred thirteen".
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