13211430132042 has 12 divisors (see below), whose sum is σ = 28624765286130. Its totient is φ = 4403810044008.

The previous prime is 13211430132023. The next prime is 13211430132071. The reversal of 13211430132042 is 24023103411231.

13211430132042 is a `hidden beast` number, since 1 + 3 + 2 + 11 + 430 + 13 + 204 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 12096059687721 + 1115370444321 = 3477939^2 + 1056111^2 .

It is a super-2 number, since 2×13211430132042² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13211430131997 and 13211430132015.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 366984170317 + ... + 366984170352.

Almost surely, 2^{13211430132042} is an apocalyptic number.

13211430132042 is an abundant number, since it is smaller than the sum of its proper divisors (15413335154088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13211430132042 is a wasteful number, since it uses less digits than its factorization.

13211430132042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 733968340677 (or 733968340674 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 13211430132042 its reverse (24023103411231), we get a palindrome (37234533543273).

The spelling of 13211430132042 in words is "thirteen trillion, two hundred eleven billion, four hundred thirty million, one hundred thirty-two thousand, forty-two".