Search a number
-
+
132115704121 is a prime number
BaseRepresentation
bin111101100001010110…
…1011010100100111001
3110122000101000011001201
41323002231122210321
54131033110012441
6140405414014201
712354643645642
oct1730255324471
9418011004051
10132115704121
1151036963a35
1221731347361
13c5c630066b
1465744826c9
15368397dc31
hex1ec2b5a939

132115704121 has 2 divisors, whose sum is σ = 132115704122. Its totient is φ = 132115704120.

The previous prime is 132115704107. The next prime is 132115704143. The reversal of 132115704121 is 121407511231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68290755625 + 63824948496 = 261325^2 + 252636^2 .

It is an emirp because it is prime and its reverse (121407511231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132115704121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132115704121.

It is not a weakly prime, because it can be changed into another prime (132115704151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057852060 + 66057852061.

It is an arithmetic number, because the mean of its divisors is an integer number (66057852061).

Almost surely, 2132115704121 is an apocalyptic number.

It is an amenable number.

132115704121 is a deficient number, since it is larger than the sum of its proper divisors (1).

132115704121 is an equidigital number, since it uses as much as digits as its factorization.

132115704121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 28.

The spelling of 132115704121 in words is "one hundred thirty-two billion, one hundred fifteen million, seven hundred four thousand, one hundred twenty-one".