Base | Representation |
---|---|
bin | 10011001110011101101… |
… | …011001011100000110001 |
3 | 11200022020201110101110022 |
4 | 103032131223023200301 |
5 | 133121304234132004 |
6 | 2450541231413225 |
7 | 164311401162401 |
oct | 23163553134061 |
9 | 4608221411408 |
10 | 1321200302129 |
11 | 46a355143a44 |
12 | 194083384215 |
13 | 97786370c06 |
14 | 47d3703c801 |
15 | 2457a23b2be |
hex | 1339dacb831 |
1321200302129 has 4 divisors (see below), whose sum is σ = 1321203671040. Its totient is φ = 1321196933220.
The previous prime is 1321200302119. The next prime is 1321200302141. The reversal of 1321200302129 is 9212030021231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1321200302129 - 24 = 1321200302113 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1321200302098 and 1321200302107.
It is not an unprimeable number, because it can be changed into a prime (1321200302119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1004777 + ... + 1911014.
It is an arithmetic number, because the mean of its divisors is an integer number (330300917760).
Almost surely, 21321200302129 is an apocalyptic number.
It is an amenable number.
1321200302129 is a deficient number, since it is larger than the sum of its proper divisors (3368911).
1321200302129 is an equidigital number, since it uses as much as digits as its factorization.
1321200302129 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3368910.
The product of its (nonzero) digits is 1296, while the sum is 26.
The spelling of 1321200302129 in words is "one trillion, three hundred twenty-one billion, two hundred million, three hundred two thousand, one hundred twenty-nine".
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