Base | Representation |
---|---|
bin | 11110000010100111010010… |
… | …000100010010110011110001 |
3 | 122022210122102120210102002211 |
4 | 132002213102010102303301 |
5 | 114304132313403130413 |
6 | 1144555320002412121 |
7 | 36554266606444321 |
oct | 3602472204226361 |
9 | 568718376712084 |
10 | 132121013333233 |
11 | 39109230703411 |
12 | 12999b30061041 |
13 | 5894c5bc2b882 |
14 | 248a9967b3281 |
15 | 1041b8649383d |
hex | 7829d2112cf1 |
132121013333233 has 16 divisors (see below), whose sum is σ = 133016815170000. Its totient is φ = 131228087058432.
The previous prime is 132121013333213. The next prime is 132121013333249. The reversal of 132121013333233 is 332333310121231.
It is a happy number.
It can be written as a sum of positive squares in 8 ways, for example, as 47933910658624 + 84187102674609 = 6923432^2 + 9175353^2 .
It is a cyclic number.
It is not a de Polignac number, because 132121013333233 - 229 = 132120476462321 is a prime.
It is a super-2 number, since 2×1321210133332332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132121013333195 and 132121013333204.
It is not an unprimeable number, because it can be changed into a prime (132121013333203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 602112903 + ... + 602332291.
It is an arithmetic number, because the mean of its divisors is an integer number (8313550948125).
Almost surely, 2132121013333233 is an apocalyptic number.
It is an amenable number.
132121013333233 is a deficient number, since it is larger than the sum of its proper divisors (895801836767).
132121013333233 is a wasteful number, since it uses less digits than its factorization.
132121013333233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225924.
The product of its (nonzero) digits is 17496, while the sum is 31.
Adding to 132121013333233 its reverse (332333310121231), we get a palindrome (464454323454464).
The spelling of 132121013333233 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, thirteen million, three hundred thirty-three thousand, two hundred thirty-three".
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