Base | Representation |
---|---|
bin | 10011001110011110010… |
… | …100000110111100001011 |
3 | 11200022021110122111010021 |
4 | 103032132110012330023 |
5 | 133121320011000212 |
6 | 2450542253401311 |
7 | 164311561316656 |
oct | 23163624067413 |
9 | 4608243574107 |
10 | 1321211031307 |
11 | 46a360201a32 |
12 | 194086a99237 |
13 | 9778865963b |
14 | 47d3863289d |
15 | 2457b15a307 |
hex | 1339e506f0b |
1321211031307 has 2 divisors, whose sum is σ = 1321211031308. Its totient is φ = 1321211031306.
The previous prime is 1321211031293. The next prime is 1321211031311. The reversal of 1321211031307 is 7031301121231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1321211031307 - 235 = 1286851292939 is a prime.
It is not a weakly prime, because it can be changed into another prime (1321211031347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660605515653 + 660605515654.
It is an arithmetic number, because the mean of its divisors is an integer number (660605515654).
Almost surely, 21321211031307 is an apocalyptic number.
1321211031307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321211031307 is an equidigital number, since it uses as much as digits as its factorization.
1321211031307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 1321211031307 its reverse (7031301121231), we get a palindrome (8352512152538).
The spelling of 1321211031307 in words is "one trillion, three hundred twenty-one billion, two hundred eleven million, thirty-one thousand, three hundred seven".
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