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1321212113233 is a prime number
BaseRepresentation
bin10011001110011110011…
…000001111000101010001
311200022021112200110020121
4103032132120033011101
5133121320300110413
62450542332510241
7164311603444165
oct23163630170521
94608245613217
101321212113233
1146a360880891
1219408731b381
1397788947c2c
1447d38834ca5
152457b2c0b8d
hex1339e60f151

1321212113233 has 2 divisors, whose sum is σ = 1321212113234. Its totient is φ = 1321212113232.

The previous prime is 1321212113189. The next prime is 1321212113311. The reversal of 1321212113233 is 3323112121231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 694410555969 + 626801557264 = 833313^2 + 791708^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321212113233 - 29 = 1321212112721 is a prime.

It is a super-2 number, since 2×13212121132332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1321212113198 and 1321212113207.

It is not a weakly prime, because it can be changed into another prime (1321212113033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660606056616 + 660606056617.

It is an arithmetic number, because the mean of its divisors is an integer number (660606056617).

Almost surely, 21321212113233 is an apocalyptic number.

It is an amenable number.

1321212113233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321212113233 is an equidigital number, since it uses as much as digits as its factorization.

1321212113233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 1321212113233 its reverse (3323112121231), we get a palindrome (4644324234464).

The spelling of 1321212113233 in words is "one trillion, three hundred twenty-one billion, two hundred twelve million, one hundred thirteen thousand, two hundred thirty-three".