Base | Representation |
---|---|
bin | 1100000001000011010010… |
… | …0011011101000111000011 |
3 | 1201210002000000022220221001 |
4 | 3000100310203131013003 |
5 | 3212432041441041003 |
6 | 44033333522512431 |
7 | 2532356442320455 |
oct | 300206443350703 |
9 | 51702000286831 |
10 | 13212201112003 |
11 | 42342990a4a33 |
12 | 1594743505717 |
13 | 74ab9c9c559a |
14 | 33968c7162d5 |
15 | 17da2dd5561d |
hex | c04348dd1c3 |
13212201112003 has 4 divisors (see below), whose sum is σ = 13215780687928. Its totient is φ = 13208621536080.
The previous prime is 13212201111913. The next prime is 13212201112009. The reversal of 13212201112003 is 30021110221231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13212201112003 - 229 = 13211664241091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13212201112009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1789782426 + ... + 1789789807.
It is an arithmetic number, because the mean of its divisors is an integer number (3303945171982).
Almost surely, 213212201112003 is an apocalyptic number.
13212201112003 is a deficient number, since it is larger than the sum of its proper divisors (3579575925).
13212201112003 is an equidigital number, since it uses as much as digits as its factorization.
13212201112003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3579575924.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13212201112003 its reverse (30021110221231), we get a palindrome (43233311333234).
The spelling of 13212201112003 in words is "thirteen trillion, two hundred twelve billion, two hundred one million, one hundred twelve thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •