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132122012312153 is a prime number
BaseRepresentation
bin11110000010101000001101…
…100111000110001001011001
3122022210202000012112210120002
4132002220031213012021121
5114304141340122442103
61145000003050142345
736554333426563313
oct3602501547061131
9568722005483502
10132122012312153
11391096a359a026
121299a16a7219b5
13589508ab9c066
14248aa4d3367b3
151041be4022488
hex782a0d9c6259

132122012312153 has 2 divisors, whose sum is σ = 132122012312154. Its totient is φ = 132122012312152.

The previous prime is 132122012312141. The next prime is 132122012312287. The reversal of 132122012312153 is 351213210221231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131976280776649 + 145731535504 = 11488093^2 + 381748^2 .

It is a cyclic number.

It is not a de Polignac number, because 132122012312153 - 28 = 132122012311897 is a prime.

It is a super-2 number, since 2×1321220123121532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132122012312123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061006156076 + 66061006156077.

It is an arithmetic number, because the mean of its divisors is an integer number (66061006156077).

Almost surely, 2132122012312153 is an apocalyptic number.

It is an amenable number.

132122012312153 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122012312153 is an equidigital number, since it uses as much as digits as its factorization.

132122012312153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 132122012312153 its reverse (351213210221231), we get a palindrome (483335222533384).

The spelling of 132122012312153 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, twelve million, three hundred twelve thousand, one hundred fifty-three".