Base | Representation |
---|---|
bin | 11110000010101000001101… |
… | …110001111010111111011010 |
3 | 122022210202000101212222102002 |
4 | 132002220031301322333122 |
5 | 114304141341334300132 |
6 | 1145000003231041002 |
7 | 36554333462653121 |
oct | 3602501561727732 |
9 | 568722011788362 |
10 | 132122015150042 |
11 | 391096a5158195 |
12 | 1299a16b670162 |
13 | 589508b653998 |
14 | 248aa4d874ab8 |
15 | 1041be43d3262 |
hex | 782a0dc7afda |
132122015150042 has 8 divisors (see below), whose sum is σ = 205016920060500. Its totient is φ = 63783041796544.
The previous prime is 132122015150033. The next prime is 132122015150077. The reversal of 132122015150042 is 240051510221231.
It can be written as a sum of positive squares in 2 ways, for example, as 132035244254281 + 86770895761 = 11490659^2 + 294569^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a junction number, because it is equal to n+sod(n) for n = 132122015149987 and 132122015150014.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1138982889167 + ... + 1138982889282.
Almost surely, 2132122015150042 is an apocalyptic number.
132122015150042 is a deficient number, since it is larger than the sum of its proper divisors (72894904910458).
132122015150042 is a wasteful number, since it uses less digits than its factorization.
132122015150042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2277965778480.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 132122015150042 its reverse (240051510221231), we get a palindrome (372173525371273).
The spelling of 132122015150042 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, fifteen million, one hundred fifty thousand, forty-two".
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